random string generator csharp

Code Example - random string generator csharp

                
                        private static Random random = new Random();

public static string RandomString(int length)
{
    const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
    return new string(Enumerable.Repeat(chars, length)
        .Select(s => s[random.Next(s.Length)]).ToArray());
}
                    
                
 

csharp random string

                        
                                private static Random random = new Random();
public static string RandomString(int length)
{
    const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
    return new string(Enumerable.Repeat(chars, length)
      .Select(s => s[random.Next(s.Length)]).ToArray());
}
                            
                        
 

generate random string csharp

                        
                                private static Random random = new Random();

public static string RandomString(int length)
{
    const string chars = "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz0123456789";
    return new string(Enumerable.Repeat(chars, length)
      .Select(s => s[random.Next(s.Length)]).ToArray());
}

public static string[] RandomStrings_Type1(int strLength, int arraySize)
{
	const string chars = "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz0123456789";
  	string[] strArray = new string[arraySize];
    for (int i = 0; i < strArray.Length; i++)
    {
  		string randomString = new string(Enumerable.Repeat(chars, length)
                                     .Select(s => s[random.Next(s.Length)]).ToArray());
      	strArray[i] = randomString;
    }
  	return strArray;
}

public static List<string> RandomStrings_Type2(int strLength, int listSize)
{
	return RandomStrings_Type1(strLength, listSize).ToList();
}